Mathematics, 06.01.2020 20:31 donterriuscollier

# Find two consecutive integers such that seven times the first equals six times the second

Answer from: Kana81

Odd integers are always one more that an even integer:

1st: 2n+1

2nd: 2n+3

EQUATION:

7(2n+1) = 5(2n+3)

14n+7 = 10n+15

4n = 8

n = 2

1st: 2n+1 = 5

2nd: 2n+3 = 7

1st: 2n+1

2nd: 2n+3

EQUATION:

7(2n+1) = 5(2n+3)

14n+7 = 10n+15

4n = 8

n = 2

1st: 2n+1 = 5

2nd: 2n+3 = 7

Answer from: Quest

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

Answer from: Quest

step-by-step explanation:

Mathematics, 21.06.2019 20:30, raquelqueengucci25

Evaluate 8j -k+148jāk+14 when j=0.25j=0.25 and k=1k=1.

Answers: 1

Find two consecutive integers such that seven times the first equals six times the second...